1class Solution {2    public List<List<String>> groupAnagrams(String[] strs) {3        Map<String, List<String>> map = new LinkedHashMap<>();4        for (String s : strs) {5            char[] chars = s.toCharArray();6            Arrays.sort(chars);7            String key = new String(chars);8            map.computeIfAbsent(key, x -> new ArrayList<>()).add(s);9        }10        return new ArrayList<>(map.values());11    }12}